Melbourne (Australia) – The great campaign of João Fonseca, 10th pre-classified in the Australian Open youth bracket, gained a new chapter this Wednesday, with a great victory over Japanese Rei Sakamoto, seed 6, closing the game in sets direct and with the final score of 6/3 and 6/4, in just 64 minutes.
The first Brazilian to reach the quarterfinals in Melbourne since 2010, when Tiago Fernandes won the title, Fonseca is now waiting for Belgian Alexander Blockx, third favorite and his partner in the duo, or Bulgarian Adriano Dzhenev, seed 15.
Although he won another one without losing a set, the 16-year-old from Rio started the game with a scare and saved two break-points in the first game. In the sixth, he took the first chance he had and broke his rival. Fonseca saved another break against in the seventh and then went on to lead 1-0.
The second partial was more balanced and with less chance of breaking. The only disputed break-points came in the third game, in which Sakamoto saved two but couldn’t resist the third. It was then enough for the Brazilian to manage the advantage until the end with good games of service and thus stamp the passport towards the quarterfinals.
Fonseca once again served very well and won 72% of the disputed points, against 65% of Sakamoto. The carioca committed three unforced errors less than the Japanese (16 to 19), but also scored three winning balls less (13 to 16).